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I finally figured out why my custom CUDA kernels were hitting

PyTorch's `.view()` method fails on non-contiguous tensors created by `.transpose()`, throwing a RuntimeError because the underlying memory layout has scrambled strides. The fix is calling `.contiguous()`, which forces a memory copy and can hurt GPU throughput in training loops; using `.reshape()` instead is safer as it handles copies automatically. The article explains the shape-versus-stride distinction and why transposition swaps strides without moving data.

read3 min views1 publishedSep 1, 2026
I finally figured out why my custom CUDA kernels were hitting
Image: Promptcube3 (auto-discovered)

.view()

, .reshape()

, or .transpose()

and assume the underlying memory stays organized. But if you're trying to optimize an AI workflow or write high-performance training loops, you cannot ignore how strides and memory layouts actually function under the hood.Most people visualize a tensor as a multi-dimensional grid, like a 3D cube of numbers. That's fine for a mental model, but it's a lie when it comes to hardware. In reality, your RAM is a flat, one-dimensional line of addresses. The "shape" is just an interpretation of how we jump through that line.

The difference between shape and strides #

When you define a tensor, you have the shape

(the dimensions) and the stride

(the number of steps to skip in memory to reach the next element in a specific dimension). This is where the real bugs hide.

If I have a 2x3 tensor:

import torch
x = torch.tensor([[1, 2, 3], [4, 5, 6]])
print(x.shape)   # torch.Size([2, 3])
print(x.stride()) # (3, 1)

The stride (3, 1)

tells PyTorch: "To move down one row, skip 3 elements. To move one column over, skip 1 element." This works perfectly because the data is contiguous.

The "Contiguous" trap #

The headache started when I used .transpose()

. When you transpose a tensor, PyTorch doesn't actually move the data around in memory—it's too slow to do that every time. Instead, it just swaps the strides.

y = x.t()
print(y.shape)   # torch.Size([3, 2])
print(y.stride()) # (1, 3)
print(y.is_contiguous()) # False

Now the tensor is "non-contiguous." The elements are logically in a new order, but physically, they are still sitting in the old order in your RAM.

This is a huge problem when you try to use certain operations like .view()

. I kept getting this specific error:RuntimeError: view size is not compatible with input tensor's size and stride (at least one dimension spans much more than 1 stride)

The error happens because .view()

requires the tensor to be contiguous. It wants to re-interpret the memory layout without copying anything, but if the strides are scrambled from a transpose, the math doesn't line up.

How to fix it (and when not to) #

If you hit that error, the quick fix is usually:

z = y.contiguous().view(new_shape)

Calling.contiguous()

forces PyTorch to allocate a new block of memory and copy the elements into the correct physical order. But here is the deep dive takeaway: .contiguous()

is not free. It’s a memory copy operation. If you are doing this inside a tight training loop for every single batch, you are effectively killing your GPU throughput.

Instead of constantly calling .contiguous()

, try to design your AI agent or model architecture to minimize transpositions, or use .reshape()

instead of .view()

. While .view()

is strict about memory, .reshape()

is smarter—it will return a view if possible, but if the tensor is non-contiguous, it will automatically handle the copy for you. It’s a bit more "beginner-friendly," but for real-world deployment, knowing exactly when a copy is happening is the difference between a model that runs in 10ms and one that drags at 50ms.

Next TimesFM-3 →

All Replies (3) #

.stride()

when debugging those weird dimension mismatches.

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